Construction Coordinator Practice Exam

What is the approximate attenuation through 1,600 feet of 0.750 cable at 600 MHz and 120° F?

1. 20.0 dB

2. 22.05 dB

3. 15.6 dB

4. 25.4 dB

The correct answer is: 22.05 dB

To determine the approximate attenuation through 1,600 feet of 0.750 cable at a frequency of 600 MHz and a temperature of 120° F, it is essential to understand how cable attenuation works. Attenuation is typically expressed in decibels (dB) and represents the loss of signal strength as it travels through the cable. The specific cable type and conditions—like the frequency and temperature—affect the attenuation value. In this case, at 600 MHz, which is a relatively high frequency, one can expect increased attenuation due to the skin effect, dielectric losses, and other frequency-related losses. Additionally, as the temperature rises, the dielectric loss also often increases, contributing further to signal loss. For a 0.750 cable, industry standards and attenuation specifications indicate that at 600 MHz, the cable may exhibit certain attenuation characteristics, especially when validated against temperature corrections. After performing calculations based on provided cable attenuation charts, or using established formulas that account for distance, frequency, temperature, and the specific type of coaxial cable, one would arrive at the attenuation value close to 22.05 dB for this scenario. This represents a realistic expectation for the signal loss over the specified distance and conditions, supporting